my number is (moderately) bigger

log(15^2000^110)

edit: les go first message on page 3

ARGH I forgor this post had multiple pages
anyway edit time!!!!!
log(15^2000^110) * 10^6

Can't jump from e240 to e308 in one message...
...->e240->e308->e333->e363->205020 why would you go all the way back down there->
e270->e310->e350->

googol^4
it's important to make sure that it's clear whether exponents would be applied from left to right or right to left as well

(total youtube users*4)^45

googol^5

555^200

ln(2.8^600)^log_200(200^^2)

oops accidentally posted something again UGDIYDGUDFH
anyways my number is 1e602

googol^7

10,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,001

sqrt(googol^15)

nobody posting game, prob nobody have a early game progress...
365!
my next progress post is incremental adventure (not sure i can get the post lucky), it like between ee10 and ee100 i dont really remember
i will check when it reach ee10, we can prob go tetration speed at eee10

sqrt(googol^17)

10^900

e1000

10^(10000/9) = 1.29154966501e1111

10^1234

(googol^1.5)^9

10^^2.614 ≈ 1.8258e1493

8^2000

10^^2.625 ≈ 6.8334e1806

also 8^2000 ≈ 1.5135e1806 (I think this jump is too big), so close lol

let's make the two last increases more consistent
...->e1493->(8^2000)/googol->e1806->
10^(current year)

2^7200

2^(2^13)

2^(2^(40/3))

10^^2.66 ≈ 9.4467e3483

e4000 why not

10^^2.68 ≈ 1.000005e5266

^^^ this one is so cool, don't bother me because of the big jump

10^(10000*2/3)

10^^2.7 ≈ 1.0468e8210

1 million root of 10^^3
(also where do you find tetration calculators)

10^(years since agriculture was discovered)
We've come so far...
exponentiation limit becomes 10 at ee10, increases as number increases too. will eventually become exponentiation of exponent

10^(7*the number in my username)

(from left to right)
10^2^2^17^5^2^5^5

10^10^4.5

adoplayzz says:

10^10^4.5

too large, ill say
...->e14000->e17000-> e31000-> e22000->
e30k

10^Monaco's population

balleater2000 says:

(also where do you find tetration calculators)

https://tetrationforum.org/showthread.php?tid=1760 << this

anyways, 10^2.77 ≈ 1.4149e52077

my number is 1 TVgMI-NTgCe (e69420 yay)
Some useful page
http://www.mrob.com/pub/math/numbers.html
http://www.mrob.com/pub/comp/hypercalc/hypercalc-javascript.html
https://aarextiaokhiao.github.io/projects/standard-conversion.html

10^((7^7^7^6)^(4*8)) (around e80000)

10^2.79 ≈ 1.4499e97648

I feel like we need to speed up even quicker at some point

adoplayzz says:

10^((7^7^7^6)^(4*8)) (around e80000)

are you sure u did not calculate wrong? 10^(7^7) is already 10^823543
and time for the classic things on number battle - making notation!
define n^!=n^n-1^n-2...^2^1
formal define is prob n^! = n^((n-1)^!) and 1^!=1 but idc the first one easier to understand
btw the letter notation we use in our incremental game is also a notation that made for number battle forum game as i remember
sqrt(5^!) ~ 2.5e91615
(actual reason is i dont have any good number to use)
Jeno47 says:

10^^2.79 ≈ 1.4499e97648

I feel like we need to speed up even quicker at some point

oh shit that was fast, jeno posted e97648, so im going to skip e100000(even its a milestone) and go for sqrt((5^!)^1.5) = ~1.25e137423 (cuz you asked for speedup, btw too much edit lol)

10^2.8110^^2.81 ≈ 1.1066e193276

Bit too fast at the end... Also did you mean to say 10^^2.81?
I'll change the last four messages to
...->e80000->e100000->e130000->e170000->
then e222222
Shouldn't take less than 6 messages to reach e1e6

wjyg says:

adoplayzz says:

10^((7^7^7^6)^(4*8)) (around e80000)

are you sure u did not calculate wrong? 10^(7^7) is already 10^823543
and time for the classic things on number battle - making notation!
define n^!=n^n-1^n-2...^2^1
formal define is prob n^! = n^((n-1)^!) and 1^!=1 but idc the first one easier to understand
btw the letter notation we use in our incremental game is also a notation that made for number battle forum game as i remember
sqrt(5^!) ~ 2.5e91615
(actual reason is i dont have any good number to use)
Jeno47 says:

10^^2.79 ≈ 1.4499e97648

alright yes i completly miscalculated that... recalculated it and it was accualy ee80000
but ye im gonna go safe now since i keep messing up the calculation

e300000

(1e600)^600

10^^2.833 ≈ 8.7763e456819

sqrt(e1e6)

10^^2.84 ≈ 1.4051e603982

7^^3 ~ 3.76e695974
we will get micrillion very soon, and then we will have some si prefix time (nope)

Bit too far still...
...->e500000-> e603982->e695974-> e580000->e670000->

2.03699^^5=~e777426

galaxyuser63274 says:

Bit too far still...
...->e500000-> e603982->e695974-> e580000->e670000->

2.03699^^5=~e777426

Its more like you too slow
ee5.94188 (its looks like a random number, but hope you don't know why its not )

wjyg says:

galaxyuser63274 says:

Bit too far still...
...->e500000-> e603982->e695974-> e580000->e670000->

2.03699^^5=~e777426

Its more like you too slow
ee5.94188 (its looks like a random number, but hope you don't know why its not )

Reread the first post
1 million base-10 orders of magnitude

2^4,000,000 = 9.6085e1,204,119

2.5^4000000 = ~e1.59e6

3.2^4,000,000 = 8.1899e2,020,599

10^((kurzgesagt's sub count as of june 5th 2024)/10)

10^^2.88 = 1.5752e3,562,238

Balancing...
...->e1.59e6->e2.02e6-> e2.27e6->e3.56e6-> e2.6e6->e3.3e6->
7^(5.00e6)= ~e4.23e6

10^^2.89 = 5.1042e5,854,515

Balancing...
...->e3.3e6->e4.23e6-> e5.85e6-> e5.6e6->
(((((((8.5))))))^7777777) = ~e7.23e6

10^10^6.9

10^10^6.9

huh why did it double post

e9.00e6

10^Azerbaijan's population as of june 6th 2024

10^^2.905 = 1.79e12,907,190

10^(10^7.15)

10^^2.91 = 2.2339e17,016,076

e2.22e7

10^^2.92 = 5.2341e30,187,000

Balancing...
...->e1.70e7->e2.22e7-> e3.02e7-> e2.95e7->
e3.92e7

1e50,000,000

e7.77e7

Way too far...
...e3.92e7->e5.00e7-> e7.77e7-> e6.66e7->
1.56e89,999,927

remember fgh? we reach a big milestone!
f3(3) ~ 6.9e121210694
while f4 will be much, much later
or, if the galaxyuser63274 dont like it, i can just use ee8

7.23e160,000,192

2.048e204,820,482

10.000001^250,000,000 = 7.2005e250,000,010

4.35e333,333,056

10^^2.96 = 6.4348e406,752,887

1e100^^1.069^0.69 = e548,086,481

random number, 6.4288e745,659,414

1.56e1.00e9 (precise: 1.56e1,000,000,781)

warning: ee10 coming soon!
1.392781243e1248163264
time to check it every day to make sure that i don't miss my game progress

e1.1e9.2

4.32e2.43e9 (precise: 4.32e2,434,554,934)
All messages between ee10 and 1F5 MUST have the approximate scientific notation (eee...eXeY or eee...eeX) for their numbers in the message or they will NOT count

3.42e2,435,453,394

3.42e3.44e9 (precise: 3.42e3,435,453,394)

10^^2.99 = 3.391e4,205,460,835

BanaCubed says:

3.42e2,435,453,394

on no my eyes

galaxyuser63274 says:

4.32e2.43e9 (precise: 4.32e2,434,554,934)
All messages between ee10 and 1F5 MUST have the approximate scientific notation (eee...eXeY) for their numbers in the message or they will NOT count

a question: which notation do we use after 10{10}10? BEAF or BAN? hyper E? bashicu matrix? fgh with ordinal? or keep use the letter notation(too bad its current only define up to ε0)

btw this is just a question post, so im not going to give a good number
one of my favorite game is eeo, so let just assume that o=9.7 so we get ~ e5.0118e9

Use the letter notation (E-F-G-H-J-K-L-M) with the E-H ~ f_n(x) and the J-M ~ f_w+n(x) and all that from 1F5 up until MMMMMMMMM10, that will probably be enough answers for a long while and if we ever go beyond MMMMMMMMM10 i'll figure something out

Oh, anyways 1.76e7.01e9 (precise: 1.76e7,013,254,391)

One post away from a new extractable E!!!!

10^^3 = 1e1e10

EE10 MILESTONE REACHED

11^^3 = ~1e1.5e10

Incorrect equality but I'm assuming your number is 1e1.5e10

You can now go crazy with exponentiation; 3.16e5.12e11 (precise: 3.16e511,782,912,003)

10^^3.05 = 1.574e1.7142e12 =1.574e1,714,269,347,227